I am planning on controlling the temperature of a box, probably of less of than 1 m3 in volume. I did not want to bother anyone with the details of the project but it now seems appropriate. I measured the intensity going through the ventilators and indeed, the Wattage I gave was the one they can dissipate. I think I could go for a lower cable gauge, I will let you know! Taking the Gauge 12 wire from your table: Wire resistance = 5.21 Ohm/km = 0.00521 Ohm/m * 1 m = 0.00521 Ohm The regulator can be set exactly to the required voltage (it is not a car but a plug adapter what supplies energy). I think you might be able to get but with 2 mm wire but 2.5 mm is much safer. Voltage drop will be 22 a * wire resistance = _ Your current will be slightly larger ~ 22 amps because a car is not 12V but 13 - 14 volts (when running). You can estimate the length, remember your length must include both the positive and negative wires.Ĭurrent = watts / volts so 225 / 12 = 18.7 Amps. You need the resistance of the wire, look here wire chart I guess the best idea would be either to limit the System output or as you mentioned, use a more powerful adapter. I guess that if the system draws full power, my arduino (also connected to this power source), will not get enough power. I would suggest to use a 12V, 25A adapter instead. In the OP, you state that the devices draw a total of about 230 Watts, or around 19 Amperes from a nominal 12V source. If this JDT-001 is the power adapter you plan to use, it won't work. The other part of the cable will be very small and will be enclosed in an insulated box, together with the rest of the electronics.Įxcellent, I will check the maximum temperature tolerated by the cable, together with the mentioned calculation of the heat emitted. I guess I could calculate the exposed cable heat emission and work out how much it will heat the environmnent. My primary objective is that the cable does not burn. That means that, since the peltier will be cooling, it will only reduce the output of the Peltier. Most of the cable will be on the cold side of the Peltier (less than 1 m3 in volume). From a 12V source, a drop of 1V means that 8% of the available power is wasted just heating up the wire.Īs I said, it will be running only occasionally. You decide on how much voltage drop can be tolerated, and then buy wire of at least the minimum diameter. The total voltage drop along a wire is easily calculated from the maximum current (I), the total length of the wire carrying the current (L) and the resistance per unit length (rho), which you can look up in the wire table.
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